cuda.tile.equal

cuda.tile.equal(x, y, /)

Compare two tiles elementwise with ==.

Can also use builtin operation x == y.

Parameters:

• x (Tile) – LHS tile.

• y (Tile) – RHS tile.

The shape of x and y will be broadcasted and dtype promoted to common dtype.

Return type:

Tile

Examples

>>> # tile and tile
>>> tx = ct.arange(8, dtype=ct.int32) - 4
>>> ty = ct.arange(8, dtype=ct.int32)
>>> tz = ct.equal(tx, ty)

>>> # Can also use the builtin op
>>> tz = tx == ty

>>> # shape broadcast
>>> tx = ct.arange(8, dtype=ct.int32)
>>> ty = ct.full((1,), 0, dtype=ct.int32)
>>> tz = tx == ty

>>> # dtype broadcast
>>> tx = ct.arange(8, dtype=ct.int32) - 4
>>> ty = ct.arange(8, dtype=ct.int64)
>>> tz = tx == ty

>>> # tile and scalar
>>> tx = ct.arange(8, dtype=ct.int32) - 4
>>> tz = tx == 0

>>> # scalar and scala
>>> z = 5 == 3