cuda.tile.equal#

cuda.tile.equal(x, y, /)#

Compare two tiles elementwise with ==.

Can also use builtin operation x == y.

Parameters:

x (Tile) – LHS tile.
y (Tile) – RHS tile.

The shape of x and y will be broadcasted and dtype promoted to common dtype.

Return type:: Tile

Examples

SnippetComplete Example

tx = ct.arange(4, dtype=ct.int32)
print(tx == 2)

import cuda.tile as ct
import torch

@ct.kernel
def kernel():
    tx = ct.arange(4, dtype=ct.int32)
    print(tx == 2)


torch.cuda.init()
ct.launch(torch.cuda.current_stream(), (1,), kernel, ())
torch.cuda.synchronize()

Output

[0, 0, 1, 0]