cudf.core.groupby.DataFrameGroupBy.nth#
- property DataFrameGroupBy.nth[source]#
Take the nth row from each group if n is an int, otherwise a subset of rows.
Like pandas, supports both the call form
gb.nth(n, dropna=...)and the index formgb.nth[n].- Parameters:
- nint, slice or list of ints and slices
A single nth value for the row, a slice with non-negative step or a list of nth values and slices. Negative values count from the end of each group.
- dropna{‘any’, ‘all’, None}, default None
Apply the specified dropna operation before counting which row is the nth row. Only supported in the call form and not currently implemented in cuDF (raises
NotImplementedError; falls back to pandas undercudf.pandas).
- Returns:
- Series or DataFrame
The nth row(s) of each group, keeping the original index and row order (like a filter operation, the group keys are not added as an index level).
Examples
>>> import cudf >>> df = cudf.DataFrame({"A": [1, 1, 2, 1, 2], ... "B": [None, 2, 3, 4, 5]}) >>> gb = df.groupby("A") >>> gb.nth(0) A B 0 1 <NA> 2 2 3 >>> gb.nth(-1) A B 3 1 4 4 2 5 >>> gb.nth[:2] A B 0 1 <NA> 1 1 2 2 2 3 4 2 5